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Using a directrix of y = β2 and a focus of (1, 6), what quadratic function is created?
4 months ago
Q:
Using a directrix of y = β2 and a focus of (1, 6), what quadratic function is created?
Accepted Solution
A:
(x-h)Β²=4p(y-k), the focus is (h, k+p), the directrix is y=k-p
in this case, h=1, Β k+p=6, k-p=-2, so k=2, p=4
so the equation is (x-1)Β²=16(y-2)